난이도: Medium
문제 설명
You are given a 0-indexed string s and a 0-indexed integer array spaces that describes the indices in the original string where spaces will be added. Each space should be inserted before the character at the given index.
- For example, given s = "EnjoyYourCoffee" and spaces = [5, 9], we place spaces before 'Y' and 'C', which are at indices 5 and 9 respectively. Thus, we obtain "Enjoy Your Coffee".
Return the modified string after the spaces have been added.
문제 예시
Example 1
Input: s = "LeetcodeHelpsMeLearn", spaces = [8,13,15]
Output: "Leetcode Helps Me Learn"
Explanation:
The indices 8, 13, and 15 correspond to the underlined characters in "LeetcodeHelpsMeLearn".
We then place spaces before those characters.
Example 2
Input: s = "icodeinpython", spaces = [1,5,7,9]
Output: "i code in py thon"
Explanation:
The indices 1, 5, 7, and 9 correspond to the underlined characters in "icodeinpython".
We then place spaces before those characters.
Example 3
Input: s = "spacing", spaces = [0,1,2,3,4,5,6]
Output: " s p a c i n g"
Explanation:
We are also able to place spaces before the first character of the string.
제한 사항
- 1 <= s.length <= 3 * 10^5
- s consists only of lowercase and uppercase English letters.
- 1 <= spaces.length <= 3 * 10^5
- 0 <= spaces[i] <= s.length - 1
- All the values of spaces are strictly increasing.
✏️ Solution(솔루션)
class Solution:
def addSpaces(self, s: str, spaces: List[int]) -> str:
s = list(s)
for space in spaces:
s[space] = f' {s[space]}'
return ''.join(s)
먼저, s 문자열을 list로 바꿔주었다. (ex. 'abc' → ['a', 'b', 'c'])
그 후 바꾼 list에서 spaces에 저장된 위치의 요소에 앞에 공백을 추가하여 저장했다.
예를 들어, 만약 input이 s = 'abc'이고 spaces = [1] 이라고 한다면 ['a', ' b', 'c']와 같이 저장된다.
마지막으로 이 list를 join함수를 통해 문자열로 변환하여 반환하면 된다.